Mostrando las entradas con la etiqueta strict factorization system. Mostrar todas las entradas
Mostrando las entradas con la etiqueta strict factorization system. Mostrar todas las entradas

23 de noviembre de 2017

The Zappa-Szép product, strict factorization systems and distributive laws

$\newcommand{\con}{\mathbf{Set}} \newcommand{\uno}{\mathbf{1}} \newcommand{\Cat}{\mathbf{Cat}}\newcommand{\mon}{\mathbf{Mon}} \newcommand{\ab}{\mathbf{Ab}} \newcommand{\an}{\mathbf{An}}\newcommand {\matcon}{\mathbf{Set\text{-}Mat}} \newcommand{\grp}{\mathbf{Grp}} \newcommand{\ob}{\mathrm{Ob}}$

The Zappa-Szép product and distributive laws


The Zappa-Szép product, strict factorization systems and distributive laws are related in a certain way. Let us talk first about the Zappa-Szép product (also known as knit product or matched pair of groups).
     The Zappa-Szép product is a generalization of the semidirect product for groups in the same way as this product is a generalization of the direct product for groups, and the zappa-szép product is the most general way in which a group is presented as a product of two groups.
     The internal Zappa-Szép product is defined as follows. Given a group $G$ and two subgroups $H$ and $K$ of $G$, the following statements are equivalent:
  • $G=KH$ y $K\cap H=\{e\}$,
  • for every $g\in G$ there is a unique $k\in K$ and a unique $h\in H$ such that $g=kh$.
If either of these statements is satisfied, then $G$ is said to be an internal Zappa-Szép product of $K$ and $H$.
     There is an external version of the Zappa-Szép product, which is the one we are interested in, because it's by means of this product that a link between distributive laws and strict factorization systems is established.
     Given two groups $K$ and $H$, suppose there are funtions $\alpha:H\times K\rightarrow K$ and $\beta:H\times K\rightarrow H$ such that
  1. $\alpha(h_1h_2,k)=\alpha(h_1,\alpha(h_2,k))$,
  2. $\beta(h_1h_2,k)=\beta(h_1,\alpha(h_2,k))\beta(h_2,k)$,
  3. $\beta(h,k_1k_2)=\beta(\beta(h,k_1),k_2)$,
  4. $\alpha(h,k_1k_2)=\alpha(h,k_1)\alpha(\beta(h,k_1),k_2)$,
  5. $\alpha(e,k)=k$,
  6. $\beta(h,e)=h$
for every $h,h_1,h_2\in H$ y $k,k_1,k_2\in K$ (cf. [4]). Note that from (ii) and (v) and from (iv) and (vi) follows respectively:
  1. $\beta(e,k)=e$ and
  2. $\alpha(h,e)=e$.
We can define from (i)-(vi) a multiplication and an inverse on $K\times H$ as $$(k_1,h_1)\gamma(k_2,h_2):=(k_1\alpha(h_1,k_2),\beta(h_1,k_2)h_2))$$ and $$(k,h)^{-1}:=(\alpha(h^{-1},k^{-1}),\beta(h^{-1},k^{-1})).$$ $(\gamma,K\times H)$ is called an external Zappa-Szép product of $K$ and $H$.
     Note that if $G$ is an internal Zappa-Szép product of its subgroups $K$ y $H$, then there are funtions $\alpha:H\times K\rightarrow K$ and $\beta:H\times K\rightarrow H$ such that (i), (ii), (iii), (iv), (v) and (vi) in the previous definition are satisfied: their existence follows from the fact that every element $g\in G$ can be written uniquely as a product $kh$, and the fact that if $G$ is an external Zappa-Szép product of the groups $K$ and $H$, then $G$ is an internal Zappa-Szép product of its subgroups $K\times e_H$ and $e_K\times H$.
     Let $H,K\in\grp$. Let $S$ and $T$ be the endofunctors $H\times(-)$ and $K\times(-)$ on $\con$, respectively. Then we have the monads $$H\times X,\quad\xymatrix{X\ar[r]^(.4){e_H\times 1_X} & H\times X},\quad\xymatrix{H\times H\times X\ar[r]^(.6){m_H\times 1_X} & H\times X}$$ and $$K\times X,\quad\xymatrix{X\ar[r]^(.4){e_K\times 1_X} & K\times X},\quad\xymatrix{K\times K\times X\ar[r]^(.6){m_K\times 1_X} & K\times X}.$$ Denote their units and multiplicationss as $\eta',\mu'$ y $\eta,\mu$, resp. Let $\gamma$ be a group structure on $K\times H$ such that $K\times e_H,e_K\times H$ are subgroups of $(\gamma,K\times H)$ and $(K\times e_H)\gamma(e_K\times H)=(\gamma,K\times H)$. In other words, such that $(\gamma,K\times H)$ is an internal Zappa-Szép product of $K\times e_H$ and $e_k\times H$, or that $(\gamma, K\times H)$ is an external Zappa-Szép product of $K$ and $H$.
     Without loss of generality, we can assume $(k,h)=(k,e_H)\gamma(e_K,h)$ for any $k\in K$ and $h\in H$ (consider the definition of external Zappa-Szép product and the properties of $\alpha$ and $\beta$). Then we have the monad $$(K\times H\times(-),(e_K,e_H)\times 1_{(-)}, \gamma\times 1_{(-)})$$ on $\con$. Since $K\times e_H$ and $e_K\times H$ are subgroups of $(\gamma,K\times H)$, then $\eta S$ and $T\eta'$ are morphisms of monads, and since $(k,h)=(k,e_H)\gamma(e_K,h)$, the previous monad satisfies the middle unitary law, so the monad above induces a distributive law $ST\Rightarrow TS$; namely, $$(\gamma\times 1_{(-)})\cdot\eta ST\eta':H\times K\times(-)\Rightarrow K\times H\times(-);$$ explicitly, $$\xymatrix{(h,k,-)\ar@{|->}[r] & (e_K,h,k,e_H,-)\ar@{|->}[r] & ((e_K,h)\gamma(k,e_H),-)}.$$
     Conversely, let $\lambda:ST\Rightarrow TS$ be a distributive law of $S$ over $T$, and consider $\lambda 1:H\times K\times 1\rightarrow K\times H\times 1$. Neglect the singleton, and put $$\lambda 1=(\alpha,\beta),$$ where $\alpha$ and $\beta$ are determined by the following commutative diagram: $$\xymatrix{ & H\times K\ar[d]^{\lambda 1}\ar[dr]^\alpha\ar[dl]_\beta &\\ K & K\times H\ar[l]^{p_K}\ar[r]_{p_H} & H. }$$ Then, by the compatibility of $\lambda$ with the unit of $S$, $$\xymatrix{ & H\times K\times 1\ar[dd]^{\lambda 1}\\ K\times 1\ar[ur]^{e_H\times K\times 1}\ar[dr]_{K\times e_H\times 1} &\\ & K\times H\times 1 }$$ commutes; hence, $\alpha(e_H,k)=k$ y $\beta(e_H,k)=e_H$.
     Now, by the compatibility of $\lambda$ with the multiplication of $S$, $$\xymatrix{ H\times H\times K\times 1\ar[rr]^{H\times\lambda 1}\ar[d]_{m_H\times K\times 1} & & H\times K\times H\times 1\ar[rr]^{\lambda_{H\times 1}} & & K\times H\times H\times 1\ar[d]^{K\times m_H\times 1}\\ H\times K\times 1\ar[rrrr]_{\lambda 1} & & & & K\times H\times 1 }$$ commutes; whence, $$\alpha(h_1h_2,k)=\alpha(h_1,\alpha(h_2,k))\quad\text{y}\quad \beta(h_1h_2,k)=\beta(h_1,\alpha(h_2,k))\beta(h_2,k).$$ Similarly, by the compatibility of $\lambda$ with the unit and the multiplication of $T$, $\alpha(h,e_K)=e_K$, $\beta(h,e_K)=h$ and $$\alpha(h,k_1k_2)=\alpha(h,k_1)\alpha(\beta(h,k_1),k_2)\quad\text{y}\quad\beta(h,k_1k_2)=\beta(\beta(h,k_1),k_2).$$
     Therefore, we have a Zappa-Szép product of $K$ and $H$.
     Thus we have a correspondence between the Zappa-Szép products of $K$ and $H$, and the distributive laws of $H\times(-)$ over $K\times(-)$. Indeed, define $L:\mathbf{Zappa\text{-}Sz\acute{e}p}(K,H)\rightarrow\mathbf{DistLaw}(H,K)$, a function which goes from the Zappa-Szép products of $K$ and $H$ to the distributive laws of $H\times(-)$ ovoer $K\times(-)$ (let $\alpha:H\times K\rightarrow K$ and $\beta:H\times K\rightarrow H$ be the functions which define a Zappa-Szép product of $K$ and $H$): $$\xymatrix{ \mathbf{Zappa\text{-}Sz\acute{e}p}(K,H)\ar[r]^(.55)L & \mathbf{DistLaw}(H,K) }\qquad\qquad\quad$$ $$\xymatrix{ (\alpha,\beta)\ar@{|->}[r] & (\alpha,\beta)\times 1_{(-)}. }$$ Define $N:\mathbf{DistLaw}(H,K)\rightarrow\mathbf{Zappa\text{-}Sz\acute{e}p}(K,H)$ as $$\xymatrix{ \mathbf{DistLaw}(H,K)\ar[r]^(.45)N & \mathbf{Zappa\text{-}Sz\acute{e}p}(K,H) }\qquad\qquad\quad$$ $$\xymatrix{ \lambda\ar@{|->}[r] & (p_K\circ\lambda 1,p_H\circ\lambda 1). }$$ Obviously $NL=1$. Less obvious is that $LN=1$. Since $\con$ is a distributive category, \begin{equation}\label{D:distcatset} Z\times X=\sum\nolimits_{x\in X}Z\times H\times\{x\}. \end{equation}
     Consider now the injection $i_x:\{x\}\rightarrow X$; then by naturality of $\lambda$, the following diagram commutes: $$\xymatrix{ H\times K\times\{x\}\ar[rr]^{H\times K\times i_x}\ar[d]_{\lambda_{\{x\}}} & & H\times K\times X\ar[d]^{\lambda_X}\\ K\times H\times\{x\}\ar[rr]_{K\times H\times i_x} & & K\times H\times X. }$$ On the other hand, since $H\times K\times i_x$ is the injection $$\xymatrix{H\times K\times\{x\}\ar[r] & \sum_{x\in X}H\times K\times\{x\}},$$ $K\times H\times i_x$ is the injection $$\xymatrix{K\times H\times\{x\}\ar[r] & \sum_{x\in X}K\times H\times\{x\}}$$ and the equality \eqref{D:distcatset} holds, $\lambda_X=\sum_{x\in X}\lambda_{\{x\}}$. However $\lambda_{\{x\}}=\lambda 1\times 1_{\{x\}}$ for every $x\in X$, so $\lambda_X=\lambda 1\times 1_X$. Hence, $\lambda_X=(p_K\circ\lambda 1,p_H\circ\lambda 1)\times 1_X$.


The bicategory of set-valued matrices


The Zappa-Szép product is generalized in [3] by showing the equivalence of the concept of distributive law in the bicategory of set-valued matrices and the concept of strict factorization system. Let's see how that is done. First describe the bicategory of set-valued matrices $\matcon$ as follows: the objects (the 0-cells) of $\matcon$ are sets, a 1-cell $M:A\rightarrow B$ is a set-valued matrix, i. e., $M(b,a)\in\con$ for every $a\in A$ and $b\in B$, a 2-cell $\tau:M\Rightarrow N:A\rightarrow B$ is a matrix of functions $\tau(b,a):M(b,a)\rightarrow N(b,a)$. The composite of 1-cells $$\xymatrix{ A\ar[r]^M & B\ar[r]^E & C\ar@{}|{=}[r] & A\ar[r]^{EM} & C }$$ is defined as $$EM(c,a):=\sum_{a\in A}E(c,b)\times M(b,a).$$ Given $A\in\matcon$, we define $$1_A(b,a):= \begin{cases} 1,\text{ the singleton, if $b=a$};\\ \emptyset,\text{ if $b\neq a$}. \end{cases}$$ It is clear that $M 1_A\overset{r}{\cong} M$ and $1_B M\overset{l}{\cong} M$.
     A monad $T$ on an object $A$ in this bicategory is precisely a category with set of objects $A$. Let's shed some light on what is happening. Diagrammatically $T$ is determined by the following commutative diagrams: $$\xymatrix{ (TT)T\ar@{}|{\cong}[r]\ar[d]_{\mu T} & T(TT)\ar[r]^(.55){T\mu} & TT\ar[d]^\mu\\ TT\ar[rr]_\mu & & T }$$ and $$\xymatrix{ 1_AT\ar[r]^{\eta T}\ar[dr]_l & TT\ar[d]^\mu & T1_A\ar[l]_{T\eta}\ar[ld]^r\\ & T &, }$$ where $l$ and $r$ are the isomorphisms above induced by the product and the terminal object of $\con$. Now, what $T$ does is to assign to each pair of elements $b,a\in A$ a set $T(b,a)$ of arrows, to give a composite to each composable pair by means of $\mu$, to choose an identity for each element $a\in A$ via $\eta$ and finally, with the previous diagrams, to make composition associative and make composition with an identity a unit law for the arrows of the small category $A$ with objects its elements and its arrows in $T(b,a)$; put differently, a monad in $\matcon$ is a category.
     Now let $M$ and $E$ be two categories with set of objects $A$ and let $\lambda:ME\Rightarrow EM$ be a distributive law of $M$ over $E$; $\lambda$ yields a function $$\xymatrix{ ME(a,c)\ar[r]^{\lambda(a,c)} & EM(a,c) }$$ for every pair $(a,c)\in A\times A$. Thus we have a family of functions $$(\xymatrix{ M(a,b)\times E(b,c)\ar[r] & \sum_{i\in A}E(a,i)\times M(i,c) })_{b\in A}.$$ If we write $m:\xymatrix{a\ \ar@{>->}[r] & b}$ for an arrow in $M$ and $e:\xymatrix{b\ar@{->>}[r] & c}$ for an arrow in $E$, then $\lambda$ yields an object $e_\lambda m$ and a composable pair $(e_\alpha m,e_\beta m)$ as shown by: $$\xymatrix{ a\; \ar@{>->}[r]^m\ar@{->>}[d]_{e_\alpha m}\ar@{}|{\triangleleft\scriptscriptstyle{\dashv}}[dr] & b\ar@{->>}[d]^e\\ e_\lambda m\;\ar@{>->}[r]_{e_\beta m} & c. }$$ We call a diagram such as this a $\lambda$-square. Consider the compatibility diagrams for the distributive law $\lambda:ME\Rightarrow EM$: \begin{equation} \vcenter{\xymatrix{ & ME\ar[dd]^\lambda\\ E\ar[ru]^{1E}\ar[dr]_{E1} & \\ & EM, }}\quad\text{compatibility of $\lambda$ with $1$ (CuM)}\notag \end{equation} \begin{equation} \vcenter{\xymatrix{ & ME\ar[dd]^\lambda\\ M\ar[ur]^{M1}\ar[dr]_{1 M} &\\ & EM, }}\quad\text{compatibility of $\lambda$ with $1$ (CuE)}\notag \end{equation} \begin{equation} \vcenter{\xymatrix{ MME\ar[r]^{M\lambda}\ar[d]_{\bullet E} & MEM\ar[r]^{\lambda M} & EMM\ar[d]^{E\bullet}\\ ME\ar[rr]_\lambda & & EM, }}\quad\text{compatibility of $\lambda$ with $\bullet$ (CmM)}\notag \end{equation} \begin{equation} \vcenter{\xymatrix{ MEE\ar[r]^{\lambda E}\ar[d]_{M\bullet} & EME\ar[r]^{E\lambda} & EEM\ar[d]^{\bullet M}\\ ME\ar[rr]_\lambda & & EM, }}\quad\text{compatibility of $\lambda$ with $\bullet$ (CmE)}\notag \end{equation} where we denote by 1 the transformations that provide identities and by $\bullet$ the transformations that provide the composites (the units and the multiplications of the monads $M$ and $E$). Now, in terms of $\lambda$-squares, the compatibility of $\lambda$ with the units is expressed by $$\xymatrix{ b\;\ar@{>->}[r]^{1_b}\ar@{->>}[d]_e\ar@{}|{\triangleleft\scriptscriptstyle{\dashv}}[dr] & b\ar@{->>}[d]^e & & a\;\ar@{>->}[r]^m\ar@{->>}[d]_{1_a}\ar@{}|{\triangleleft\scriptscriptstyle{\dashv}}[dr] & b\ar@{->>}[d]^{1_b}\\ c\;\ar@{>->}[r]_{1_c} & c & & a\;\ar@{>->}[r]_m & b; }$$ i. e., CuM and CuE state that ${1_b}_\lambda e=c,m_\lambda 1_b=a$ and that
  1. ${1_b}_\alpha e=e$,
  2. ${1_b}_\beta e=1_c$,
  3. $m_\alpha 1_b=1_a$,
  4. $m_\beta 1_b=m$.
Chasing the upper right path of the diagram of CmM yields $$\xymatrix{ a\;\ar@{>->}[rr]^m\ar@{->>}[d]_{m_\alpha(n_\alpha e)}\ar@{}|{\triangleleft\scriptscriptstyle{\dashv}}[drrrr] & & b\;\ar@{>->}[rr]^n & & b''\ar@{->>}[d]^e\\ m_\lambda(n_\alpha e)\;\ar@{>->}[rr]_{m_\beta(n_\alpha e)} & & n_\lambda e\;\ar@{>->}[rr]_{n_\beta e} & & c; }$$ chasing the left lower path, $(mn)_\lambda e=m_\lambda(n_\alpha e)$ and
  1. $(mn)_\alpha e=m_\alpha(n_\alpha e)$,
  2. $(mn)_\beta e=m_\beta(n_\alpha e)\bullet n_\beta e$.
Similarly, for CmE, if we chase the upper right paht of the diagram, then $$\xymatrix{ a\;\ar@{>->}[rr]^m\ar@{->>}[d]_{m_\alpha e}\ar@{}|{\triangleleft\scriptscriptstyle{\dashv}}[ddrr] & & b\;\ar@{->>}[d]^e\\ m_\lambda e\ar@{->>}[d]_{(m_\beta e)_\alpha f} & & b'\ar@{->>}[d]^f\\ (m_\beta e)_\lambda f\;\ar@{>->}[rr]_(.55){(m_\beta e)_\beta f} & & c; }$$ chasing the left lower path, $m_\lambda(ef)=(m_\beta e)_\lambda f$ and
  1. $m_\alpha(ef)=m_\alpha e\bullet(m_\beta e)_\alpha f$,
  2. $m_\beta(ef)=(m_\beta e)_\beta f$.
If $A$ has a single element, then $M$ and $E$ are monoids, the equations (I)-(VIII) are the equations (i)-(viii) and the equalities for objects are trivial.
     From the general theory of distsributive law [1], $\lambda$ induces a composite monad $E_\lambda M$, a category with set of objects $A$ in which an arrow from $a$ to $c$ is given by specifying a third object $b$ and a pair $$\xymatrix{ a\ar@{->>}[r]^e & b\;\ar@{>->}[r]^m & c }$$ with $e$ in $E$ and $m$ in $M$; i. e., the arrows in $E_\lambda M$ are described as a formal composition $e\circ m$. The composition in $E_\lambda M$ is given by the multiplication for the monad $E_\lambda M$; namely, by $$\xymatrix{ & & EEM\ar[dr]^{\bullet M} & \\ EMEM \ar[r]^{E\lambda M} & EEMM\ar[ur]^{EE\bullet}\ar[dr]_{\bullet MM}\ar[rr]^(.55){\bullet\;\bullet} & & EM\\ & & EMM\ar[ur]_{E\bullet} &, }$$ thus the composite of $a\overset{e}{\twoheadrightarrow} b\overset{m}{\rightarrowtail} c$ and $c\overset{f}{\twoheadrightarrow} d\overset{n}{\rightarrowtail} x$ is given by $$\xymatrix{ a\ar@{->>}[r]^e\ar@{->>}[dr]_{e\bullet m_\alpha f} & b\;\ar@{>->}[r]^m\ar@{->>}[d]_(.35){m_\alpha f}\ar@{}|{\triangleleft\scriptscriptstyle{\dashv}}[dr] & c\ar@{->>}[d]^f\\ & m_\lambda f\;\ar@{>->}[r]_(.6){m_\beta f}\ar@{>->}[dr]_{m_\beta f\bullet n} & d\ar@{>->}[d]^n\\ & & x; }$$ i. e., $(e\circ m)\bullet(f\circ n)=(e\bullet m_\alpha f)\circ(m_\beta f\bullet n)$.
     It is easy to check that the unit of the composite monad $E_\lambda M$ characterizes the identities in $E_\lambda M$ by $$a\overset{1_a}{\twoheadrightarrow}a\overset{1_a}{\rightarrowtail}a.$$
     The morphisms of monads $1M:M\rightarrow E_\lambda M$ and $E1:E\rightarrow E_\lambda M$ are given by $m\mapsto 1\circ m$ and $e\mapsto e\circ 1$, resp. The middle unitary law yields that for every $e\circ m$ in $E_\lambda M$, $$(e\circ 1)\bullet(1\circ m)=e\circ m$$ holds.
     Note that if $M$ and $E$ are monoids, the composition in $E_\lambda M$ is the multiplication defined in the case of the Zappa-Szép product for groups.
     There is a greater generalization of the Zappa-Szép product in [2]; however, things there are done more à la Ehresmann.


Strict factorization systems


Given a category $C$ with $\ob(C)=:A$, a strict factorization system on $C$ is a pair of subcategories $S:=(E,M)$ of $C$ such that $\ob(M)=\ob(E)=\ob(C)$ and such that for every $f$ in $C$, there is a unique factorization $f=e_fm_f$ with $e_f$ in $E$ and $m_f$ in $M$. Consider $M$ and $E$ as monads on $A$ in $\matcon$. The pair $(E,M)$ induces a distributive law $\lambda_S:ME\Rightarrow EM$; indeed, define $\lambda_S$ by $$\xymatrix{ ME\ar[r]^{\lambda_S} & EM }$$ $$\xymatrix{ a\ar[r]^n & b\ar[r]^f & c\ar@{|->}[r] & a\ar[r]^{e_{n\cdot f}} & i\ar[r]^{m_{n\cdot f}} & c. }\ $$ Its compatibility with the unit of $M$ is obvious, for $m\cdot 1_b=m$. Now, the upper right path of the compatibility diagram of $\lambda_S$ with respect to the multiplication of $M$ (check the diagram above) produces the following diagram: $$\xymatrix{ a\ar[rr]^f\ar[dr]_{e_{f\cdot e_{g\cdot h}}} & & b\ar[r]^g\ar[dr]_(.45){e_{g\cdot h}} & c\ar[r]^h & d\\ & k\ar[rr]_{m_{f\cdot e_{g\cdot h}}} & & j\ar[ur]_{m_{g\cdot h}} &\ ; }$$ so $f\cdot g\cdot h$ has as factorization $e_{f\cdot e_{g\cdot h}}\cdot m_{f\cdot e_{g\cdot h}}\cdot m_{g\cdot h}$, which is unique; whence, the left lower path in the compatibility diagram of $\lambda_S$ with respect to the multiplication of $M$ produces the same result, and in consequence the compatibility of $\lambda_S$ with $M$ is satisfied. Similarly, the compatibility of $\lambda_S$ with $E$ is satisfied.
     Conversely, let $\lambda:ME\Rightarrow EM$ be a distributive law in $\matcon$, and consider the subcategories of $E_\lambda M$ defined by $$\lambda E:=\{e\circ 1\mid e\in E\}\quad\text{y}\quad M\lambda:=\{1\circ m\mid m\in M\}.$$ Each of these subcategories contains all the identities of $E_\lambda M$ and thus each contains all the objects of $E_\lambda M$. By the middle unitary law, $e\circ m$ is factorized as $(e\circ 1)\bullet(1\circ m)$. It is clear that this factorization is unique, and therefore $(\lambda E, M\lambda)$ is a strict factorization system $S_\lambda$ for $E_\lambda M$.
     We leave this correspondence just right there; i. e., we won't show that $S_{(-)}$ and $\lambda_{(-)}$ are biequivalences inverse of each other, because this is not our objetive right now.
     The way a distributive law is induced by the Zappa-Szép product in the group case makes us wonder whether a distributive law in $\matcon$ participates in a correspondence of that kind...


References


[1] Beck, J. [1969]: Distributive laws, Seminar on Triples and Categorical Homological Theory, ETH 1966/67, 80, 119-140 (1969).
[2] Brin, M. G. [2005]: On the Zappa-Szép Product, Communications in Algebra, 33, 393-424 (2005).
[3] Rosebrugh, R., Wood, R. J. [2002]: Distributive laws and factorization, Journal of Pure and Applied Algebra, 175(1-3), 327-353 (2002).
[4] Takeuchi, M. [1981]: Matched pairs of groups and bismash products of Hopf algebras, Communications in Algebra, 9(8), 841-882 (1981).